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+// N-Queen
+//
+// The original is written as a Lisp program in the following file:
+// https://www.istc.kobe-u.ac.jp/activity/mage/m27/27_Lisp.pdf
+
+
+/**
+ * member
+ * r, done << member(m, list)
+ * return
+ * r: 1 if m occurs in list
+ * done: the same to `list'
+ */
+// fun member x [] = false
+// | member x (y::ys) = if x=y then true else (member x ys);
+
+member(r, list, int x) >< [] =>
+ r~0, list~[];
+member(r, list, int x) >< (int y):ys
+| x==y =>
+ r~1, list~y:ys
+| _ =>
+ list~y:cnt, member(r, cnt, x)~ys;
+
+
+/**
+ * len_list (stream version)
+ * len, done << len_list(list)
+ * return
+ * len: length of `list'
+ * done: the same to `list'
+ */
+
+len_list(len, done) >< [] =>
+ len~0, done~[];
+len_list(len, done) >< x:xs =>
+ done~x:cnt,
+ len_list_(len, cnt, 1)~xs;
+
+len_list_(len, done, int ct) >< [] =>
+ len~ct, done~[];
+len_list_(len, done, int ct) >< x:xs =>
+ done~x:cnt,
+ len_list_(len, cnt, ct+1) ~ xs;
+
+/**
+ * len (non-stream version)
+ * ret << len(list)
+ * return
+ * ret: length of `list'
+ */
+
+len(ret) >< [] =>
+ ret~0;
+len(ret) >< x:xs =>
+ len_list(ret, Eraser)~x:xs;
+
+
+
+/**
+ * threat (stream version)
+ * check for (0,q) and (k, qpos[col=k]) where k=1...
+ * http://www.nct9.ne.jp/m_hiroi/func/haskell06.html
+ 0 1 2 -->
+ +-------------
+ 1| . . . . . .
+ 2| . . . -3. . 5 - 3 = 2
+ 3| . . -2. . . 5 - 2 = 3
+ 4| . -1. . . . 5 - 1 = 4
+ 5| Q . . . . . Q position is 5
+ 6| . +1. . . . 5 + 1 = 6
+ 7| . . +2. . . 5 + 2 = 7
+ 8| . . . +3. . 5 + 2 = 8
+ +-------------
+ * r, done << threat(k,m, board)
+ * return
+ * r: 1 if threat conditions are satisfied
+ * done: the same to `board'
+ */
+// fun threat k m [] = false
+// | threat k m (x::xs) =
+// if (k = x-m) orelse (k = x+m) then true
+// else (threat (k+1) m xs);
+
+threat(r, done, int k, int q)><[] =>
+ r~0, done~[];
+threat(r, done, int k, int q)><(int x):xs
+| (k == x-q) or (k == q-x) =>
+ r~1, done~(x:xs)
+| _ =>
+ done~x:cnt, threat(r, cnt, k+1, q)~xs;
+
+
+
+// fun queen1 b n 0 = []
+// | queen1 b n m =
+// if (member m b) orelse (threat 1 m b) then (queen1 b n (m-1))
+// else if (length b) = (n-1) then (m::b)::(queen1 b n (m-1))
+// else (queen1 (m::b) n n) @ (queen1 b n (m-1));
+// fun queen n = queen1 n [] n;
+
+queen(ret) >< (int n) => queen_(ret, [], n)~n;
+
+queen_(r, b, int n) >< (int m)
+| m==0 =>
+ r~[], Eraser~b
+| _ =>
+ mem_ret, done_b << member(m,b),
+ queen__chk_m_in_b(r, done_b, n, m)~mem_ret;
+
+queen__chk_m_in_b(r, b, int n, int m) >< (int mem_ret)
+| mem_ret == 1 =>
+ queen_(r, b, n)~(m-1)
+| _ =>
+ th_ret, done_b << threat(1, m, b),
+ queen__chk_threat(r, done_b, n, m)~th_ret;
+
+queen__chk_threat(r, b, int n, int m) >< (int threat_ret)
+| threat_ret == 1 =>
+ queen_(r, b, n)~(m-1)
+| _ =>
+ len_ret, done_b << len_list(b),
+ queen__chk_lastelem(r, done_b, n, m)~len_ret;
+
+queen__chk_lastelem(r, b, int n, int m) >< (int len_ret)
+| len_ret == n-1 =>
+ b1, b2 << Dup(b),
+ r~(m:b1):cnt, queen_(cnt, b2, n)~(m-1)
+| _ =>
+ b1, b2 << Dup(b),
+ r << Append(cnt1, cnt2),
+ queen_(cnt1, m:b1, n)~n, queen_(cnt2, b2, n)~(m-1);
+
+
+
+// ----------------------------------------------------------
+// main
+// ----------------------------------------------------------
+const N=12;
+queen(ret)~N, len(count)~ret;
+count; // count ->14200